1. What is Specific Consumption?

Specific consumption (g/kWh) is a measure of fuel or mass flow rate relative to power output. It indicates how many grams of a substance are consumed per kilowatt-hour of energy produced.

2. How Does the Calculator Work?

The calculator uses the conversion formula:

Where:

• \( kg/h \) — Mass flow rate in kilograms per hour
• \( Power\_kW \) — Power output in kilowatts
• \( 1000 \) — Conversion factor (kg to g)

Explanation: The formula converts the mass flow rate from kg/h to g/h (by multiplying by 1000) and then divides by the power output to get consumption per kWh.

3. Importance of Specific Consumption

Details: Specific consumption is crucial for evaluating engine or system efficiency, comparing performance across different systems, and monitoring fuel or resource usage in industrial processes.

4. Using the Calculator

Tips: Enter mass flow rate in kg/h and power output in kW. Both values must be positive numbers. The calculator will automatically convert to g/kWh.

5. Frequently Asked Questions (FAQ)

Q1: Why convert kg/h to g/kWh?
A: g/kWh is a standard unit for specific fuel consumption and allows for easier comparison between different systems regardless of their size.

Q2: What are typical values for specific consumption?
A: Diesel engines typically range 200-250 g/kWh, gas turbines 300-400 g/kWh, but values vary widely by technology and operating conditions.

Q3: Can this be used for any substance?
A: Yes, the calculation works for any mass flow (fuel, water, chemicals) where you want to relate consumption to power output.

Q4: What if my power is in HP instead of kW?
A: First convert HP to kW (1 HP ≈ 0.7457 kW) before using this calculator.

Q5: How precise is this conversion?
A: The calculation is mathematically exact, but practical accuracy depends on the precision of your input measurements.